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Emil Renner Berthing authored
On x86 chars are signed, but we're comparing a char to '0' + unsigned int, which is promoted to an unsigned int. Let's promote the char to unsigned before doing the comparison to avoid weird corner cases.
fdd6fa38
On x86 chars are signed, but we're comparing a char to '0' + unsigned int, which is promoted to an unsigned int. Let's promote the char to unsigned before doing the comparison to avoid weird corner cases.